Integrand size = 36, antiderivative size = 197 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=\frac {2 \sqrt {2} a^{3/2} (i A+B) \text {arctanh}\left (\frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {8 a (7 i A+8 B) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {4 (21 i A+19 B) (a+i a \tan (c+d x))^{3/2}}{105 d} \]
[Out]
Time = 0.80 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3675, 3678, 3673, 3608, 3561, 212} \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=\frac {2 \sqrt {2} a^{3/2} (B+i A) \text {arctanh}\left (\frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}+\frac {2 a (8 B+7 i A) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {4 (19 B+21 i A) (a+i a \tan (c+d x))^{3/2}}{105 d}-\frac {8 a (8 B+7 i A) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d} \]
[In]
[Out]
Rule 212
Rule 3561
Rule 3608
Rule 3673
Rule 3675
Rule 3678
Rubi steps \begin{align*} \text {integral}& = \frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}+\frac {2}{7} \int \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)} \left (\frac {1}{2} a (7 A-6 i B)+\frac {1}{2} a (7 i A+8 B) \tan (c+d x)\right ) \, dx \\ & = \frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}+\frac {4 \int \tan (c+d x) \sqrt {a+i a \tan (c+d x)} \left (-a^2 (7 i A+8 B)+\frac {1}{2} a^2 (21 A-19 i B) \tan (c+d x)\right ) \, dx}{35 a} \\ & = \frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {4 (21 i A+19 B) (a+i a \tan (c+d x))^{3/2}}{105 d}+\frac {4 \int \sqrt {a+i a \tan (c+d x)} \left (-\frac {1}{2} a^2 (21 A-19 i B)-a^2 (7 i A+8 B) \tan (c+d x)\right ) \, dx}{35 a} \\ & = -\frac {8 a (7 i A+8 B) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {4 (21 i A+19 B) (a+i a \tan (c+d x))^{3/2}}{105 d}-(2 a (A-i B)) \int \sqrt {a+i a \tan (c+d x)} \, dx \\ & = -\frac {8 a (7 i A+8 B) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {4 (21 i A+19 B) (a+i a \tan (c+d x))^{3/2}}{105 d}+\frac {\left (4 a^2 (i A+B)\right ) \text {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,\sqrt {a+i a \tan (c+d x)}\right )}{d} \\ & = \frac {2 \sqrt {2} a^{3/2} (i A+B) \text {arctanh}\left (\frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {8 a (7 i A+8 B) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 a (7 i A+8 B) \tan ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 i a B \tan ^3(c+d x) \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {4 (21 i A+19 B) (a+i a \tan (c+d x))^{3/2}}{105 d} \\ \end{align*}
Time = 1.95 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.68 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=\frac {210 \sqrt {2} a^{3/2} (i A+B) \text {arctanh}\left (\frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {2} \sqrt {a}}\right )+2 a \sqrt {a+i a \tan (c+d x)} \left (-126 i A-134 B+(42 A-38 i B) \tan (c+d x)+3 (7 i A+8 B) \tan ^2(c+d x)+15 i B \tan ^3(c+d x)\right )}{105 d} \]
[In]
[Out]
Time = 0.12 (sec) , antiderivative size = 164, normalized size of antiderivative = 0.83
method | result | size |
derivativedivides | \(\frac {2 i \left (\frac {i B \left (a +i a \tan \left (d x +c \right )\right )^{\frac {7}{2}}}{7}-\frac {i B a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}}}{5}-\frac {A a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}}}{5}+\frac {i B \,a^{2} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {3}{2}}}{3}+i a^{3} B \sqrt {a +i a \tan \left (d x +c \right )}-A \,a^{3} \sqrt {a +i a \tan \left (d x +c \right )}+a^{\frac {7}{2}} \left (-i B +A \right ) \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a +i a \tan \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right )\right )}{d \,a^{2}}\) | \(164\) |
default | \(\frac {2 i \left (\frac {i B \left (a +i a \tan \left (d x +c \right )\right )^{\frac {7}{2}}}{7}-\frac {i B a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}}}{5}-\frac {A a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}}}{5}+\frac {i B \,a^{2} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {3}{2}}}{3}+i a^{3} B \sqrt {a +i a \tan \left (d x +c \right )}-A \,a^{3} \sqrt {a +i a \tan \left (d x +c \right )}+a^{\frac {7}{2}} \left (-i B +A \right ) \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a +i a \tan \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right )\right )}{d \,a^{2}}\) | \(164\) |
parts | \(\frac {2 i A \left (-\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}}}{5}-a^{2} \sqrt {a +i a \tan \left (d x +c \right )}+a^{\frac {5}{2}} \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a +i a \tan \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right )\right )}{d a}+\frac {2 B \left (-\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {7}{2}}}{7}+\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {5}{2}} a}{5}-\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {3}{2}} a^{2}}{3}-a^{3} \sqrt {a +i a \tan \left (d x +c \right )}+a^{\frac {7}{2}} \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a +i a \tan \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right )\right )}{d \,a^{2}}\) | \(189\) |
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 467 vs. \(2 (152) = 304\).
Time = 0.27 (sec) , antiderivative size = 467, normalized size of antiderivative = 2.37 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=-\frac {105 \, \sqrt {2} \sqrt {-\frac {{\left (A^{2} - 2 i \, A B - B^{2}\right )} a^{3}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {4 \, {\left ({\left (-i \, A - B\right )} a^{2} e^{\left (i \, d x + i \, c\right )} + \sqrt {-\frac {{\left (A^{2} - 2 i \, A B - B^{2}\right )} a^{3}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{{\left (-i \, A - B\right )} a}\right ) - 105 \, \sqrt {2} \sqrt {-\frac {{\left (A^{2} - 2 i \, A B - B^{2}\right )} a^{3}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {4 \, {\left ({\left (-i \, A - B\right )} a^{2} e^{\left (i \, d x + i \, c\right )} - \sqrt {-\frac {{\left (A^{2} - 2 i \, A B - B^{2}\right )} a^{3}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{{\left (-i \, A - B\right )} a}\right ) + 2 \, \sqrt {2} {\left ({\left (189 i \, A + 211 \, B\right )} a e^{\left (7 i \, d x + 7 i \, c\right )} + 7 \, {\left (57 i \, A + 53 \, B\right )} a e^{\left (5 i \, d x + 5 i \, c\right )} + 35 \, {\left (9 i \, A + 11 \, B\right )} a e^{\left (3 i \, d x + 3 i \, c\right )} + 105 \, {\left (i \, A + B\right )} a e^{\left (i \, d x + i \, c\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{105 \, {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
[In]
[Out]
\[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=\int \left (i a \left (\tan {\left (c + d x \right )} - i\right )\right )^{\frac {3}{2}} \left (A + B \tan {\left (c + d x \right )}\right ) \tan ^{2}{\left (c + d x \right )}\, dx \]
[In]
[Out]
none
Time = 0.33 (sec) , antiderivative size = 153, normalized size of antiderivative = 0.78 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=-\frac {i \, {\left (105 \, \sqrt {2} {\left (A - i \, B\right )} a^{\frac {9}{2}} \log \left (-\frac {\sqrt {2} \sqrt {a} - \sqrt {i \, a \tan \left (d x + c\right ) + a}}{\sqrt {2} \sqrt {a} + \sqrt {i \, a \tan \left (d x + c\right ) + a}}\right ) - 30 i \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {7}{2}} B a + 42 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {5}{2}} {\left (A + i \, B\right )} a^{2} - 70 i \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {3}{2}} B a^{3} + 210 \, \sqrt {i \, a \tan \left (d x + c\right ) + a} {\left (A - i \, B\right )} a^{4}\right )}}{105 \, a^{3} d} \]
[In]
[Out]
\[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=\int { {\left (B \tan \left (d x + c\right ) + A\right )} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \tan \left (d x + c\right )^{2} \,d x } \]
[In]
[Out]
Time = 9.20 (sec) , antiderivative size = 211, normalized size of antiderivative = 1.07 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^{3/2} (A+B \tan (c+d x)) \, dx=-\frac {2\,B\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{3/2}}{3\,d}-\frac {A\,a\,\sqrt {a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}\,2{}\mathrm {i}}{d}-\frac {2\,B\,a\,\sqrt {a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}}{d}-\frac {A\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{5/2}\,2{}\mathrm {i}}{5\,a\,d}+\frac {2\,B\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{5/2}}{5\,a\,d}-\frac {2\,B\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{7/2}}{7\,a^2\,d}-\frac {\sqrt {2}\,A\,{\left (-a\right )}^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}}{2\,\sqrt {-a}}\right )\,2{}\mathrm {i}}{d}-\frac {\sqrt {2}\,B\,a^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2\,\sqrt {a}}\right )\,2{}\mathrm {i}}{d} \]
[In]
[Out]